16/y=3^2+12

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Solution for 16/y=3^2+12 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

16/y = 3^2+12 // - 3^2+12

16/y-3^2-12 = 0

16*y^-1 = 21 // : 16

y^-1 = 21/16

-1 < 0

1/(y^1) = 21/16 // * y^1

1 = 21/16*y^1 // : 21/16

16/21 = y^1

y = 16/21

y = 16/21

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